Transformation ratio

                                                     Transformation ratio

Transformer primary voltage and secondary voltage ratio is transformation ratio. Is expressed by ratio a = Ep / Es

The symbol K to K = Es / Ep

Voltage transformer ratio

Transformer primary voltage and the voltage transformer secondary voltage ratio called. ratio a = Ep / Es are expressed.

The symbol K to K = Es / Ep

Transformer turn ratio

Transformer primary coil and secondary coil of the screw of the screw is ratio turn ratio. Turn ratio a = Np / Ns

The symbol K to K = Ns / Np

Transformer voltage is equal to ratio turn ratio and why?

Transformer can be seen e.m.f. Equation E = 4.44ƒNΦ

Primary voltage Ep and Np is the number of primary turn or screw

Ep = 4.44ƒNpΦ ................... (1)

The secondary voltage Es and Ns the number of secondary turn or screw

Es = 4.44ƒNsΦ ........................ (2)

Equation (1) and (2) divided by the -

Ep / Es = Np / Ns

Frequency is equal to the flux of each coil, and both have the same voltage and the voltage turn , turn ratio ratio and the same.

280 × 224 - ... to have a turns ratio of 2:3 rather than 0.667 or 100:150.

For example of mathematics

1. A 4600/230 V Transformer Secondary to the primary coil 36 of the screw of the screw and how?

Answer: - 

that is,

 Ep = 4600 V

Es = 230 V

Ns = 36

Np =?

Ep / Es = Np / Ns

Np = Ep / Es × Ns

      = 4600/230 × 36

     = 720 turns.

2. A 25Hz 2400/230 Volt single phase voltage transformer 8V per piece to determine: -

1. The number of primary and secondary screw,

2. Maximum flux cores.

Answer: -

Reply: -

Are,

ƒ = 25Hz

Ep = 2400 V

Es = 230 V

E / turn = 8 V

Np =  ?

Ns =   ?

Φm =  ?

1. Np = 2400 / 8 = 300 turns

Ns = 230/8 = 29 turns

2. Ep = 4.44ƒNpΦ

Φ = Ep / 4.44ƒNp

 = 2400 / 4.44 × 25 × 300

= 72.07 m wab.

3. A 50KVA 440/110 Volt Transformer transformer has a primary coils turn 1000. The transformer Ip, Is and Ns to determine.

Answer: -

 that is,

Rating = 50 KVA

Ep = 440 V

Es = 110 V

Np = 1000 turn

Ip =?

Is =?

Ns =?

Ip = 50 × 1000 ÷ 440 = 113.64 A

Is = Ep ÷ Es × Ip

    = 440 ÷ 110 × 113.64 = 454.54 A

Ns = Es÷ Ep × Np

    = 110 ÷ 440 × 1000

    = 250 turns.

Losses Of Transformer

                                                 Losses Of Transformer

The amount of energy received from the supply of a transformer All most can not move a load. Some of that heat energy is created out of the cores and coil. The power transformer is wasted.

Transformer loss is -

. Core loss.

. Copper loss.

The core loss of the type such as -

.  Hysteriasis loss.

. Eddy Current waste.

Many of the ideas that the transformer is no mechanical friction and the loss or misuse is not Windows?

Because of the transformer is not a rotation or running parts. Movement or rotation, so that no mechanical transformer loss or friction, and Windows is not wasted. Current waste and loss of Eddy just Hysteriasis loss or resistances copper cores are wasted.

What is the Transformer Hysteriasis loss  ?

Transformer primary and secondary Coils mutual flux is that the AC type. The cycles of the cores in a Hysteriasis flux loop proportional loss of power. Change the direction of the magnetic circuit of the core flux  demagnetizing the direction is changed, the change in magnetic molecules and inter-molecular friction attraction  heated the core of this waste.

Loss core material cores hystersis pharmabiliti, ritenatibhiti, and Frequency depends on the density of cores flux. Silicon steel is very weak hysteriasis the loop to keep a low loss silicon steel core than transformer hysteriasis used.  such as -

Low - carbon steel, nickel Iron, cobalt Iron, cobalt Iron nickel.

712 × 471 - Basic Transformer. TOPIC 2:Losses (Most significant losses). 1. Copper ...

What is the Eddy Current transformer Loss  ?

AC type transformer core and the cores Eddy mutual flux E.M.F. Is created. Eddy e.m.f.- The effect of this type cores circulating current or Eddy Current is the current flow is heated by the energy dissipation occurs in the cores.

Eddy Current transformer cores Loss area, lamination thickness, flux Supply Frequency and density dependent. Eddy Current transformer cores to reduce Loss striking the thin sheet is created and given to each of the falling insulation varnish.

Transformer how to reduce waste?

The density of the core area of ​​the (βm) transformer flux of Low, high pharmabiliti silicon steel with high susceptibility thin wall falling down to the core. All sheets  between cores insulation with varnish to reduce core and coil resistance Loss can be reduced less than the copper.

200 × 200 - copper losses in a transformer. atransformer operates on the principal of ...

For example of mathematics

1. A 20KVA 1200/120 V 50Hz transformer full-load copper loss and copper loss is 720 W when determining the tax load

1. 10 KVA

2. 5KVA

3. 15 KVA

4. 10KW and p.f. 0.8.

1. Psc = 720 (10/20) ² = 180 W.

2. Psc = 720 (5/20) ² = 45 W.

3. Psc = 720 (15/20) ² = 405 W.

4. Output = 10 / 0.8 = 12.5 KVA.

                   So that,

        Psc = 720 (12.5 / 20) ² = 281.25 W.